Post a New Question

Chemistry

posted by .

calculate the energy of a photon emitted when an electron in a hydrogen atom undergoes a transition from n=7 to n=1. Is it just 6? or how do I do this?

  • Chemistry -

    No.
    delta E = 2.180 x 10^-18 J x (1/n1^2 - 1/n2^2)
    n1 = 1 and 1^2 = 1
    n2 = 7 and 7^2 = 49
    Solve for delta E.

  • Chemistry -

    2.136 x 10^-18

Answer This Question

First Name
School Subject
Your Answer

Related Questions

More Related Questions

Post a New Question