posted by Diggs .
A 50.0 mL sample of 0.200 M AgNO3(aq) was allowed to react with an excess of NaCl(aq). The AgCl precipitate from the reaction was carefully dried and weighed. How many grams of precipitate should be obtained? I'm currently stuck and need help asap!!
AgNO3 + NaCl ==> AgCl + NaNO3
Here is a sample stoichiometry problem i posted. Just follow the instructions. moles AgNO3 = M x L.