The concentration of lead ions (Pb^2+) in a sample of polluted water that also contains nitrate ions (NO3) is determined by adding solid sodium sulfate (Na2SO4) to the sample of the water. Write the net ionic equation for the reaction. Do not forget to indicate the state of each species.

Pb^+(aq) + SO4^-2(aq) ==>PbSO4(s)

Pb^2+(aq)+SO4^2-(aq) --> PbSO4(s)

To write the net ionic equation for the reaction between lead ions (Pb^2+), nitrate ions (NO3^-), and solid sodium sulfate (Na2SO4), we need to first write the balanced chemical equation and then remove the spectator ions.

The balanced chemical equation for the reaction is:

Pb(NO3)2 (aq) + Na2SO4 (s) → PbSO4 (s) + 2NaNO3 (aq)

To write the net ionic equation, we remove the spectator ions. The spectator ions are the ones that appear on both sides of the balanced equation and do not participate in the reaction. In this case, the spectator ions are the sodium (Na+) and nitrate (NO3^-) ions.

Removing the spectator ions, the net ionic equation is:

Pb^2+ (aq) + SO4^2- (aq) → PbSO4 (s)

The state of each species is indicated as follows:

aq - aqueous (dissolved in water)
s - solid

Therefore, the net ionic equation for the reaction is:

Pb^2+ (aq) + SO4^2- (aq) → PbSO4 (s)

To write the net ionic equation for the reaction, we first need to identify the reactants and products.

Reactants:
- Lead ions (Pb^2+)
- Nitrate ions (NO3)
- Sodium sulfate (Na2SO4)

Products:
- Solid lead sulfate (PbSO4) (precipitate)
- Sodium ions (Na+)
- Nitrate ions (NO3)

Now, let's write the balanced equation for the reaction:

Pb^2+ (aq) + SO4^2- (aq) + 2Na+ (aq) + 2NO3- (aq) → PbSO4 (s) + 2Na+ (aq) + 2NO3- (aq)

To get the net ionic equation, we need to eliminate the spectator ions, which are the ions that appear on both sides of the equation and do not participate in the reaction. In this case, the sodium ions (Na+) and nitrate ions (NO3-) are spectator ions.

Net ionic equation:

Pb^2+ (aq) + SO4^2- (aq) → PbSO4 (s)

In this equation, we only include the species that participate in the reaction: lead ions (Pb^2+) and sulfate ions (SO4^2-). The sodium ions and nitrate ions are not included since they are not involved in the chemical change.

Note: (aq) represents an aqueous solution, and (s) represents a solid precipitate.