Math

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What is the domain of (sec(x)-1)/(x^2)?

  • Math -

    The domain of a function
    f(x)=g(x)/h(x) is given by
    dom(g(x))∩dom(h(x))\{x|h(x)=0}

    which means to find the domain of f(x), we calculate the intersection of the domains of g(x) and h(x), less the points at which h(x)=0 (vertical asymptotes).

    In your case,
    dom(sec(x)-1) is ℝ,
    dom(x²) is also ℝ
    All you need to do is to find
    dom(sec(x)-1) ∩ dom(x²) but exclude points at which x²=0.

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