math
posted by Emili .
What are the values of b which satisfy b square root of 11996b=1?

b  sqrt(1  1996b) = 1,
Isolate the radical:
b  1 = sqrt(1  1996b),
Square both sides:
b^2  2b + 1 = 1  1996b,
b^2  2b + 1996b = 1  1,
b^2 + 1994b = 0,
Factor out b:
b(b + 1994) = 0,
b = 0,
b + 1994 = 0,
b = 1994,
Solution set: b = 0, and b = 1994.
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