For OCTANE, what is the ratio of Carbon atoms to Hydrogen atoms in a molecule?
It's specified that Octane undergoes complete combustion to form 8L of Carbon Dioxide & 9L of Water at constant temp and pressure.
thanks :)
CxHy + O2 ==> CO2 + H2O
If it forms 8L CO2 and 9L H2O, the ratio of C/H must be 8/(2*9) or 8/18
To determine the ratio of carbon atoms to hydrogen atoms in a molecule of octane, we can use the balanced equation for its complete combustion.
The balanced equation for the complete combustion of octane is:
2 C8H18 + 25 O2 → 16 CO2 + 18 H2O
From the equation, we can see that there are 2 moles of octane (C8H18) reacting with 25 moles of oxygen (O2) to form 16 moles of carbon dioxide (CO2) and 18 moles of water (H2O).
Now, we know that the volume ratios of gases in a chemical reaction are directly proportional to the stoichiometric coefficients in the balanced equation when the reaction is carried out under the same temperature and pressure conditions.
Given that octane undergoes complete combustion to form 8 liters of carbon dioxide and 9 liters of water, we can compare these volumes to determine the ratio of carbon atoms to hydrogen atoms.
From the balanced equation, we can see that for every 2 moles of octane, we get 16 moles of carbon dioxide. This implies that for every 8 liters of carbon dioxide, there are 2 moles of octane.
Similarly, for every 2 moles of octane, we get 18 moles of water. This implies that for every 9 liters of water, there are 2 moles of octane.
So, we can conclude that for every 8 liters of carbon dioxide and 9 liters of water formed from the combustion of octane, there are 2 moles of octane, which means that the ratio of carbon atoms to hydrogen atoms is 1 to 9.
Therefore, in a molecule of octane (C8H18), the ratio of carbon atoms to hydrogen atoms is 1:9.
To determine the ratio of carbon atoms to hydrogen atoms in an octane molecule, we can look at the balanced chemical equation for the complete combustion of octane.
First, let's understand the balanced chemical equation for the combustion of octane:
2C8H18 + 25O2 → 16CO2 + 18H2O
From the equation, we can see that for every 2 molecules of octane (C8H18), 16 molecules of carbon dioxide (CO2) and 18 molecules of water (H2O) are produced.
Now, let's convert these molecules into moles. The balanced equation shows that for every 16 molecules of carbon dioxide, there are 2 molecules of octane, and for every 18 molecules of water, there are also 2 molecules of octane.
So, the ratio of carbon dioxide molecules to octane molecules is 16:2, which simplifies to 8:1.
Since each molecule of carbon dioxide contains 1 carbon atom, the ratio of carbon atoms to octane molecules is also 8:1.
Similarly, the ratio of water molecules to octane molecules is 18:2, which simplifies to 9:1. Since each molecule of water contains 2 hydrogen atoms, the ratio of hydrogen atoms to octane molecules is 18:2, which also simplifies to 9:1.
Therefore, the ratio of carbon atoms to hydrogen atoms in an octane molecule is 8:9.