A HELICOPTER hovering above a forest fire dumps a large bucket of water. How far does the water fall in the first 3.0 seconds
t=3.0s
Use:
Distance S
= ut+(1/2)gt²
u=initial velocity =0 m/s
g=acceleration due to gravaity=-9.8 m/s²
t=time in seconds.
S=vertical distance in metres.
To determine how far the water falls in the first 3.0 seconds, we need to calculate the distance traveled using the formula for free fall:
d = (1/2) * g * t^2
where:
d = distance traveled
g = acceleration due to gravity (approximately 9.8 m/s^2)
t = time (3.0 seconds)
Let's substitute the values into the formula and calculate the distance:
d = (1/2) * 9.8 * (3.0)^2
d = (1/2) * 9.8 * 9
d = 4.9 * 9
d = 44.1 meters
Therefore, the water falls approximately 44.1 meters in the first 3.0 seconds.