calculus
posted by norma .
find the rate of change of the distance between the origin and a moving point on the graph of y=x^2+2 if ds/dt=5 centimeters per second.

I will assume you meant
dx/dt = 5, or else the answer to your question is given
s = √(x^2 + y^2)
= (x^2 + (x^2+2)^2)^.5
= (x^4 + 5x^2 + 4)^.5
ds/dt = (1/2)(x^4 + 5x^2 + 4)(4x^3 + 10x)(dx/dt)
so after you plug in the value, not much else can be done
Something fishy about the question, was there an x value given? 
forgot the exponent ... should say'
ds/dt = (1/2)(x^4 + 5x^2 + 4)^(1/2)(4x^3 + 10x)(dx/dt)
Respond to this Question
Similar Questions

calculus
find the rate of change of the distance between the origin and a moving point on the graph of y=x^2+2 if ds/dt=5 centimeters per second. 
calculus
Find the rate of change of the distance between the origin and a moving point on the graph y = x^2 + 8 if dx/dt = 8 centimeters per second. 
Calculus
A particle is moving along the curve y = 2 √{3 x + 7}. As the particle passes through the point (3, 8), its xcoordinate increases at a rate of 4 units per second. Find the rate of change of the distance from the particle to … 
calculus
A particle is moving along the curve y=4((3x+1)^.5). As the particle passes through the point (5,16) its coordinate increases at a rate of 2 units per second. Find the rate of change of the distance from the particle to the origin … 
calculus
A particle is moving along the curve y=5sqrt(3x+1). As the particle passes through the point (5,20) its xcoordinate increases at a rate of 3 units per second. Find the rate of change of the distance from the particle to the origin … 
Calculus
find the rate of change of the distance between the orgin and a moving point on the graph of y=x^2+1 idf dx/dt=2 centimeters per second. 
Calculus
A particle is moving along the curve . As the particle passes through the point , its coordinate increases at a rate of units per second. Find the rate of change of the distance from the particle to the origin at this instant. 
Calculus
A particle is moving along the curve . As the particle passes through the point , its coordinate increases at a rate of units per second. Find the rate of change of the distance from the particle to the origin at this instant. 
Calculus
A particle is moving along the curve . As the particle passes through the point , its coordinate increases at a rate of units per second. Find the rate of change of the distance from the particle to the origin at this instant. 
Calculus HELP
A particle is moving along the curve y=5 sqrt (2x+6). As the particle passes through the point (5,20 , its xcoordinate increases at a rate of 5 units per second. Find the rate of change of the distance from the particle to the origin …