calculus

posted by .

find the rate of change of the distance between the origin and a moving point on the graph of y=x^2+2 if ds/dt=5 centimeters per second.

  • calculus -

    I will assume you meant
    dx/dt = 5, or else the answer to your question is given

    s = √(x^2 + y^2)
    = (x^2 + (x^2+2)^2)^.5
    = (x^4 + 5x^2 + 4)^.5
    ds/dt = (1/2)(x^4 + 5x^2 + 4)(4x^3 + 10x)(dx/dt)

    so after you plug in the value, not much else can be done
    Something fishy about the question, was there an x value given?

  • calculus -

    forgot the exponent ... should say'

    ds/dt = (1/2)(x^4 + 5x^2 + 4)^(-1/2)(4x^3 + 10x)(dx/dt)

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. calculus

    find the rate of change of the distance between the origin and a moving point on the graph of y=x^2+2 if ds/dt=5 centimeters per second.
  2. calculus

    Find the rate of change of the distance between the origin and a moving point on the graph y = x^2 + 8 if dx/dt = 8 centimeters per second.
  3. Calculus

    A particle is moving along the curve y = 2 √{3 x + 7}. As the particle passes through the point (3, 8), its x-coordinate increases at a rate of 4 units per second. Find the rate of change of the distance from the particle to …
  4. calculus

    A particle is moving along the curve y=4((3x+1)^.5). As the particle passes through the point (5,16) its -coordinate increases at a rate of 2 units per second. Find the rate of change of the distance from the particle to the origin …
  5. calculus

    A particle is moving along the curve y=5sqrt(3x+1). As the particle passes through the point (5,20) its x-coordinate increases at a rate of 3 units per second. Find the rate of change of the distance from the particle to the origin …
  6. Calculus

    find the rate of change of the distance between the orgin and a moving point on the graph of y=x^2+1 idf dx/dt=2 centimeters per second.
  7. Calculus

    A particle is moving along the curve . As the particle passes through the point , its -coordinate increases at a rate of units per second. Find the rate of change of the distance from the particle to the origin at this instant.
  8. Calculus

    A particle is moving along the curve . As the particle passes through the point , its -coordinate increases at a rate of units per second. Find the rate of change of the distance from the particle to the origin at this instant.
  9. Calculus

    A particle is moving along the curve . As the particle passes through the point , its -coordinate increases at a rate of units per second. Find the rate of change of the distance from the particle to the origin at this instant.
  10. Calculus HELP

    A particle is moving along the curve y=5 sqrt (2x+6). As the particle passes through the point (5,20 , its x-coordinate increases at a rate of 5 units per second. Find the rate of change of the distance from the particle to the origin …

More Similar Questions