find the value value of X
m<AOB=4x-2, m<BOC=5x+10 m<COD=3x-8
m<AOE = 180 and M<BOC and m<DOE are congruent angles
So
m<AOB + m<BOC + m<COD + m<DOE = 180
(4x-2)+(5x+10)+(3x-8)+(5x+10) = 180
17x+10=180
17x=170
x=10
the person is wrong
To find the value of X, we need to set up an equation using the given information. From the problem statement, we have:
m<AOB = 4x - 2
m<BOC = 5x + 10
m<COD = 3x - 8
Since the sum of angles in a straight line is 180 degrees, we can write:
m<AOB + m<BOC + m<COD = 180
Substituting the given expressions, we have:
(4x - 2) + (5x + 10) + (3x - 8) = 180
Now, let's solve the equation:
Combine like terms: 4x + 5x + 3x - 2 + 10 - 8 = 180
Combining like terms, we have: 12x = 180
Divide both sides of the equation by 12: (12x) / 12 = 180 / 12
Simplifying, we find: x = 15
Therefore, the value of X is 15.
m<AOE = 180 and M<BOC and m<DOE are congruent angles
So
m<AOB + m<BOC + m<COD + m<DOE = 180
(4x-2)+(5x+10)+(3x-8)+(5x+10) = 180
17x+10=180
17x = 170
x = 170