find the value value of X

m<AOB=4x-2, m<BOC=5x+10 m<COD=3x-8

m<AOE = 180 and M<BOC and m<DOE are congruent angles

So

m<AOB + m<BOC + m<COD + m<DOE = 180

(4x-2)+(5x+10)+(3x-8)+(5x+10) = 180

17x+10=180

17x=170

x=10

the person is wrong

To find the value of X, we need to set up an equation using the given information. From the problem statement, we have:

m<AOB = 4x - 2
m<BOC = 5x + 10
m<COD = 3x - 8

Since the sum of angles in a straight line is 180 degrees, we can write:

m<AOB + m<BOC + m<COD = 180

Substituting the given expressions, we have:

(4x - 2) + (5x + 10) + (3x - 8) = 180

Now, let's solve the equation:

Combine like terms: 4x + 5x + 3x - 2 + 10 - 8 = 180
Combining like terms, we have: 12x = 180

Divide both sides of the equation by 12: (12x) / 12 = 180 / 12
Simplifying, we find: x = 15

Therefore, the value of X is 15.

m<AOE = 180 and M<BOC and m<DOE are congruent angles

So

m<AOB + m<BOC + m<COD + m<DOE = 180

(4x-2)+(5x+10)+(3x-8)+(5x+10) = 180

17x+10=180

17x = 170

x = 170