When 83.1 moles of calcium acetate are dissolved in enough water to make 580 milliliters of solution, what is the molarity of acetate ions? Answer in units of M.

To find the molarity of acetate ions in the solution, we need to calculate the number of moles of acetate ions and then divide it by the volume of the solution in liters.

1. Calculate the number of moles of acetate ions:
Since calcium acetate dissociates into one calcium ion (Ca²⁺) and two acetate ions (C₂H₃O₂⁻), the number of moles of acetate ions will be twice the moles of calcium acetate.
Number of moles of acetate ions = 2 × number of moles of calcium acetate = 2 × 83.1 moles

2. Convert the volume of the solution to liters:
Since the given volume is in milliliters, we need to convert it to liters.
Volume of solution in liters = 580 milliliters ÷ 1000 = 0.58 liters

3. Calculate the molarity of acetate ions:
Molarity = moles of acetate ions / volume of solution in liters
Molarity = (2 × 83.1 moles) / 0.58 liters

Now, we can perform the calculation:
Molarity of acetate ions = (2 × 83.1) / 0.58
Molarity of acetate ions ≈ 286.90 M

Therefore, the molarity of acetate ions in the solution is approximately 286.90 M.

To find the molarity of acetate ions in the solution, we first need to determine the number of moles of acetate ions present.

Calcium acetate, Ca(C2H3O2)2, dissociates in water to produce one calcium ion (Ca2+) and two acetate ions (C2H3O2-).

Given that 83.1 moles of calcium acetate are dissolved in the solution, we know that there are an equal number of acetate ions. So, the number of moles of acetate ions is also 83.1 moles.

Next, we need to find the volume of the solution in liters. We have 580 milliliters of solution, which is equivalent to 580/1000 = 0.58 liters.

Finally, we can calculate the molarity of acetate ions using the formula:

Molarity (M) = Moles of solute / Volume of solution (in liters)

Molarity = 83.1 moles / 0.58 liters

Molarity = 143 M (rounded to three significant figures)

Therefore, the molarity of acetate ions in the solution is 143 M.

M = mols/L. The M of acetate ions will be twice that of the calcium acetate salt.

286.552M