when a drawing pin falls to the ground, the probability that it lands point up is 0.2. a. Find the probability that a pin does not lend point up. Two drawing pins fall one after the other.

this is a hard one

For one pin, the probability that it lands NOT point up is

P(1)=1-0.2=0.8
For two pins, dropped in succession, the probability that both do not point up is
P(1)=0.8*0.8
=0.64

To find the probability that a pin does not land point up, we can subtract the probability of landing point up (0.2) from 1.

So, the probability that a pin does not land point up is 1 - 0.2 = 0.8.

Now, let's consider the probability of both pins not landing point up when they fall one after the other.

Since the events of each pin falling are independent, the probability of both pins not landing point up is the product of their individual probabilities.

Therefore, the probability that both pins do not land point up is 0.8 * 0.8 = 0.64.

To find the probability that a pin does not land point up, we need to subtract the probability that it does land point up from 1.

Given that the probability that a pin lands point up is 0.2, the probability that it does not land point up is:

P(not point up) = 1 - P(point up)
P(not point up) = 1 - 0.2
P(not point up) = 0.8

So the probability that a pin does not land point up is 0.8.

Now, let's consider the scenario where two drawing pins fall one after the other. To find the probability of the sequence of events, we need to multiply the individual probabilities.

Assuming the events are independent (one pin falling does not affect the other pin falling), the probability of the first pin not landing point up is 0.8, and the probability of the second pin not landing point up is also 0.8.

Therefore, the probability that both pins do not land point up is:

P(both not point up) = P(not point up for Pin 1) * P(not point up for Pin 2)
P(both not point up) = 0.8 * 0.8
P(both not point up) = 0.64

So the probability that both pins do not land point up is 0.64.