Physics
posted by Rich .
a long jumper jumps 10m and leaves the ground at an angle of 45 degrees.determine the speed he leaves the the ground at,

The upward velocity is Vsin45. The horizontal veloicty is Vcos45
horizontal:
10m=Vcos45*t
time= 14.1/V
Vertical
Hfinal=hinitial+Vsin45*t 4.9t^2
put what we found in for time, solve for v.
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