Post a New Question

physics

posted by .

A ball is thrown horizontally with an initial velocity of 20.0 m/s from the edge of a building of a certain height. The ball lands at a horizontal distance of 82.0 m from the base of the building. What is the height of the building?

  • physics -

    time, t=82/20=4.05 s
    u=initial vertical velocity = 0 m/s
    Distance, S
    =ut-(1/2)gt²

    Can you take it from here?

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

More Related Questions

Post a New Question