a car traveling at 7.0 m/s accelerates uniformly at 2.5 m/s to the 2nd power to reach a speed of 12.0 m/s. how long does it take for this acceleration to occur.?
To find the time it takes for the acceleration to occur, we can use the equation:
v = u + at
where:
v = final velocity (12.0 m/s)
u = initial velocity (7.0 m/s)
a = acceleration (2.5 m/s^2)
t = time
First, rearrange the equation:
t = (v - u) / a
Substitute the values:
t = (12.0 - 7.0) / 2.5
t = 5.0 / 2.5
t = 2.0 seconds
Therefore, it takes 2.0 seconds for the car to accelerate to a speed of 12.0 m/s.
To find the time it takes for the acceleration to occur, we can use the formula:
t = (vf - vi) / a
where t is the time, vf is the final velocity, vi is the initial velocity, and a is the acceleration.
Given:
vi = 7.0 m/s
vf = 12.0 m/s
a = 2.5 m/s^2
Applying the values into the formula, we have:
t = (12.0 m/s - 7.0 m/s) / 2.5 m/s^2
Simplifying:
t = 5.0 m/s / 2.5 m/s^2
t = 2.0 s
Therefore, it takes 2.0 seconds for the acceleration to occur.