Login or Sign Up

Ask a New Question

the length of a rectangle is 9in. greater than the width.the area 36in.2 find the dimensions

L=W+9

LW=36

substitution:
(W+9)W=36
solve for W (width)

and plug that back into
L=W+9 to solve for L (length)

Similar Questions

the length of a rectangle is 9in. greater than the width.the area 36in.2 find the dimensions

Top answer: see above. Read more.
The length of a rectangle is 8 cm greater than its width. Find the dimensions of the rectangle if its area is 105 cm.How do I

Top answer: Area = Length*Width Information you are given: Area = 105cm^2 and Length = width + 8 therefore: 105 Read more.
The length of a rectangle is 1 inch greater than its width. If the dimensions are doubled, its area increases by 36 square

Top answer: L = W + 1 Since area = L * W 2L(2W) - LW = 36 Substitute W + 1 for L in second equation to find L. Read more.
the length of a rectangle is 1 inch greater than its width if its dimensions are doubled its area increases by 36 square inches

Top answer: original width -- x original length -- x+1 original area = x(x+1) new width --- 2x new length --- Read more.
Please help:The length of a rectangle is 5m greater than twice its width, and its area is 33m^2 (the m is squared). Find the

Top answer: width: w length: 2w+5 area: w(2w+5) = 33 2w^2 + 5w - 33 = 0 (w-3)(2w+11) w=3 or -11/2 width: 3 Read more.
The rectangle shown has a perimeter of 118 cm and the given area. Its length is 4 more than four times its width. Write and

Top answer: if w is the width, the length must be 4w+4 So, you need to solve 2(w + 4w+4) = 118 5w+4 = 59 w = 11 Read more.
The area of a rectangle is 105mm^2. The length is six millimeters less than three times its width. Find the dimensions of the

Top answer: b) Let w be the width of the rectangle. Then the length is 3w - 6. c) The area of a rectangle is Read more.
THE LENGTH OF A RECTANGLE IS 3M MORE THAN 2 TIMES ITS WIDTH. IF THE AREA IF THE RECTANGLE IS 99CM^2, FIND THE DIMENSIONS OF THE

Top answer: We can substitute the value of L from the first equation into the second equation: (2W + 3)W = 99 Read more.
the length of a rectangle is 1 cm less than twice its width. the area is 28 cm squared. find the dimensions of the rectangle.Jus

Top answer: width = 4 length + 7 Read more.
The length of a rectangle is 2 inches longer than the width. The area of the rectangle is 56 in^2. Find the dimensions.Also: The

Top answer: w(w+2) = 56 w^2+2w-56 = 0 w = √57 - 1 Read more.