The roadrunner leaves Pittsburgh at 7:15 in the morning at 10mph. He is headed toward Cleveland which is 131 miles away. If the coyote leaves 15 minutes later, what speed will he have to travel to get there at the same time as the road runner?
They go the same distance.
roadrunner: d=r*t
131=10*t or t= 13.1hrs
coyote:
d=rt
131=r(13.1-.25hrs)
r= 131/(12.85)
Thank you
To find out the speed at which the coyote needs to travel to arrive at the same time as the roadrunner, we can follow these steps:
Step 1: Determine the roadrunner's travel time.
The roadrunner leaves Pittsburgh at 7:15 am and travels at a constant speed of 10 mph. To calculate the time it takes for the roadrunner to reach Cleveland, we use the distance formula: time = distance ÷ speed.
Time = 131 miles ÷ 10 mph = 13.1 hours.
Step 2: Account for the roadrunner's 15-minute head start.
The coyote leaves 15 minutes (¼ hour) later than the roadrunner. So, the coyote needs to travel the same distance in 13.1 hours minus ¼ hour.
Adjusted Time = 13.1 hours - ¼ hour = 12.85 hours.
Step 3: Calculate the speed required for the coyote.
Since we know the distance (131 miles) and the adjusted time (12.85 hours), we can now determine the speed at which the coyote needs to travel.
Speed = Distance ÷ Time = 131 miles ÷ 12.85 hours ≈ 10.18 mph.
Therefore, the coyote needs to travel at approximately 10.18 mph to reach Cleveland at the same time as the roadrunner.