When the shuttle bus comes to a sudden stop to avoid hitting a dog, it decelerates uniformly at 3.8 m/s2 as it slows from 8.8 m/s to 0 m/s. Find the time interval of acceleration for the bus. Answer in units of s.
a=(vf-vi)/time
a=-3.8m/s^2
vf=0m/s
vi=8.8m/s
find time.
To find the time interval of acceleration for the bus, we can use the equation:
vf = vi + at,
where vf is the final velocity, vi is the initial velocity, a is the acceleration, and t is the time interval.
In this case, the final velocity of the bus is 0 m/s, the initial velocity is 8.8 m/s, and the acceleration is -3.8 m/s^2 (negative sign indicating deceleration).
Substituting these values into the equation, we get:
0 = 8.8 + (-3.8)t.
Simplifying the equation, we have:
-3.8t = -8.8.
Dividing both sides by -3.8, we find:
t ≈ 2.32 s.
Therefore, the time interval of acceleration for the bus is approximately 2.32 seconds.