What mass of protons would be required to just neutralize the charge of 1.7 g of electrons?
I thought it was simple because 1 proton maxes out 1 electron but my teacher started talking abou this complicated way of doing it and i didn't get it :(
can someone show me how to do this problem? Thanks
you don't have one electron.
Number of electrons=mass/massoneelectron
= .0017kg/9.11E-31kg
Now find the mass of an equal number of protons.
i got 1.1e54 for the mass of protons required but it said it was wrong
Of course! I'll explain the process step by step so you can understand how to solve the problem.
To neutralize the charge of electrons, you need an equal number of protons. Keep in mind that both protons and electrons have the same magnitude of charge but opposite signs.
Here's how you can solve the problem:
Step 1: Determine the number of electrons in 1.7 g of electrons.
To do this, you need to use the molar mass and Avogadro's number.
- The molar mass of electrons is approximately 5.486 x 10^-4 g/mol.
- Avogadro's number is approximately 6.022 x 10^23 electrons/mol.
First, convert grams to moles:
1.7 g * (1 mol / 5.486 x 10^-4 g) = 3.097 x 10^3 mol
Multiply the number of moles by Avogadro's number to find the number of electrons:
3.097 x 10^3 mol * (6.022 x 10^23 electrons / 1 mol) = 1.864 x 10^27 electrons
Step 2: Calculate the number of protons needed.
Since protons and electrons have an equal magnitude of charge, you'll need the same number of protons to neutralize the electrons.
So, the number of protons needed is also 1.864 x 10^27.
Step 3: Convert the number of protons to mass.
The mass of one proton is approximately 1.673 x 10^-24 g.
Multiply the number of protons by the mass of one proton to find the total mass of protons:
1.864 x 10^27 * (1.673 x 10^-24 g / 1 proton) = 3.113 x 10^3 g
Therefore, to just neutralize the charge of 1.7 g of electrons, you would need an approximate mass of 3.113 x 10^3 grams of protons.