I need help please, Find an equation of the line having the given slope containing the give point
m=5/6(5,-8)
5/6+ 40/6 is this correct and if not can you explain to me what I am doing wrong please
y-y1=m(x-x1)
where
m=5/6
(x1,y1)=(5,-8)
This is not right
5/6x-73/6
To find the equation of a line given its slope and a point through which it passes, you can use the point-slope form of a linear equation. The point-slope form is given by:
y - y₁ = m(x - x₁)
where m is the slope of the line, and (x₁, y₁) are the coordinates of the given point.
In this case, the slope (m) is 5/6, and the point is (5, -8). So, we substitute these values into the point-slope form:
y - (-8) = (5/6)(x - 5)
Simplifying further:
y + 8 = (5/6)(x - 5)
Now, to convert this equation into the standard form (Ax + By = C), we multiply both sides of the equation by 6 to eliminate fractions:
6(y + 8) = 5(x - 5)
Distributing:
6y + 48 = 5x - 25
Rearranging to get all the variables on one side:
5x - 6y = 73
And that's the equation of the line with the slope of 5/6 and passing through the point (5, -8).