3t(t+2)-(3t+5t) for t=19
if one factors that, one gets
t(3t+6-3-5)=t(3t-2)=19(57-2) check that.
3t(t+2)-(3t+5t) for t=19
3t(t+2)-(8t)
3(19)*(19+2)-(8*19)
57*21-152
1197-152=1045
To find the value of the expression 3t(t+2)-(3t+5t) for t=19, we can substitute t=19 into the expression and simplify.
Let's start by substituting t=19 into the expression:
3t(t+2)-(3t+5t) = 3(19)(19+2) - (3(19) + 5(19))
Simplify within the parentheses first:
= 3(19)(21) - (57 + 95)
Now, perform the multiplication:
= 3(399) - (152)
= 1197 - 152
Finally, subtract:
= 1045
Therefore, when t=19, the expression 3t(t+2)-(3t+5t) equals 1045.