write each number as the product of prime factors.
(a) 42__________________
(b) 110_________________
(c)...__________________
(d)...__________________
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42 = 2 * 21
Study this site for the rest of your assignment.
http://www.mathsisfun.com/prime-factorization.html
42=2*7*3.
Then I'd study that site.
To find the prime factorization of a number, you need to break it down into its prime factors, which are the prime numbers that divide into it evenly.
(a) 42:
To find the prime factorization of 42, determine the smallest prime number that divides it evenly. In this case, 2 is the smallest prime number that divides into 42. Divide 42 by 2, and you get 21. Continue this process until you cannot divide any further.
42 ÷ 2 = 21
Now, repeat the process with the number 21. Find the smallest prime number that divides into 21, which is 3. Divide 21 by 3.
21 ÷ 3 = 7
You have reached a prime number (7), so you cannot continue dividing any further. The prime factorization of 42 is 2 × 3 × 7.
(b) 110:
Using the same process, divide 110 by the smallest prime number, which is 2.
110 ÷ 2 = 55
Now, divide 55 by the smallest prime number, which is 5.
55 ÷ 5 = 11
Since 11 is a prime number, the prime factorization of 110 is 2 × 5 × 11.
You have not provided any numbers (c), (d), etc. If you provide additional numbers, I will gladly help you find their prime factorizations as well.