Solve the given equation for n.
12(n+9)=3(36+4n)
12(n+9)=3(36+4n)
12n+108=108+12n
-108 -108
12n=12n
12n/12=12n/12
n=n
does the answer = all real numbers then
To solve the equation 12(n+9) = 3(36+4n) for n, we will follow a step-by-step process:
Step 1: Distribute the terms on both sides of the equation.
This involves multiplying each term inside the parentheses by the number in front of the parentheses.
On the left-hand side:
12(n+9) = 12 * n + 12 * 9 = 12n + 108
On the right-hand side:
3(36+4n) = 3 * 36 + 3 * 4n = 108 + 12n
Now, the equation becomes:
12n + 108 = 108 + 12n
Step 2: Simplify the equation.
At this point, we notice that both sides of the equation are the same, 12n + 108. This means that the equation is an identity, and there are infinitely many solutions.
The solution for n is any real number.
Therefore, the equation has infinitely many solutions for n.