What is the percent composition of carbon in sodium carbonate (Na2CO3)
Na2CO3 = 12/106 x 100 = 11.32%
is this correct?
Yes, if Molmass sodium carbonate is 106, I didn't check it.
it is
To determine the percent composition of carbon in sodium carbonate (Na2CO3), you need to know the molar mass of carbon and the molar mass of the compound Na2CO3.
The molar mass of carbon (C) is approximately 12.01 g/mol.
The molar mass of sodium carbonate (Na2CO3) can be calculated by adding up the molar masses of each element present in the compound.
Na (sodium) has a molar mass of 22.99 g/mol.
C (carbon) has a molar mass of 12.01 g/mol.
O (oxygen) has a molar mass of 16.00 g/mol.
So, for Na2CO3:
(2 x 22.99 g/mol) + 12.01 g/mol + (3 x 16.00 g/mol) = 46.00 g/mol + 12.01 g/mol + 48.00 g/mol = 106.01 g/mol.
To calculate the percent composition of carbon in sodium carbonate (Na2CO3), divide the molar mass of carbon by the molar mass of Na2CO3 and multiply by 100%.
(12.01 g/mol / 106.01 g/mol) x 100% = 11.32%.
Therefore, your calculation is correct. The percent composition of carbon in sodium carbonate (Na2CO3) is approximately 11.32%.