A car accelerates at a rate of 0.6 m/s2. How long does it take for this car to from a speed of 55 mi/h to 60 mi/h?
To find the time it takes for the car to go from a speed of 55 mi/h to 60 mi/h, we can use the equation:
v = u + at
where:
v = final velocity
u = initial velocity
a = acceleration
t = time
Let's first convert the speeds from miles per hour to meters per second, as the acceleration is given in m/s^2:
1 mile = 1609.34 meters
1 hour = 3600 seconds
So, 55 mi/h is equivalent to (55 * 1609.34) / 3600 m/s, which is approximately 24.59 m/s.
Similarly, 60 mi/h is equivalent to (60 * 1609.34) / 3600 m/s, which is approximately 26.82 m/s.
Now, we can find the time it takes for the car to accelerate from 24.59 m/s to 26.82 m/s using the given acceleration of 0.6 m/s^2.
Substituting the values into the equation, we have:
26.82 = 24.59 + 0.6t
Rearranging the equation to solve for t:
0.6t = 26.82 - 24.59
0.6t = 2.23
Dividing both sides by 0.6:
t = 2.23 / 0.6
Therefore, the time it takes for the car to go from a speed of 55 mi/h to 60 mi/h is approximately t = 3.72 seconds.