Chemistry

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226Ra88 decays by emitting three alpha particles and three beta particles. what's the resulting nuclei?

Is it 238Bi83?
(Number on left is mass # and on right is atomic #)

  • Chemistry -

    I don't think so.
    88Ra226 ==>2He4 + 2He4 + 2He4 + -1e0 + -1e0 + -1e0 + X.
    88-2-2-2+1+1+1 = 88-3=85At
    (88 = 2+2+2-1-1-1 + X = 3+85)
    226 -4-4-4 = 214
    (226 = 4+4+4+X = 12 + 214
    So I think the end product is 85At214. Check my thinking.

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