Help, Can anyone show me how to do the formula to solve these equations?
4x-5y=38
7x-8y=-22
If you can show me the right way to solve, I do not understand how to get the answer.
You want to try eliminate one of the two variables (either x or y). When you do this, you're able to for one variable, plug that value in the equation and solve for the other variable.
http://www.analyzemath.com/Tutorial-System-Equations/Tutorial-System-Equations.html
When you do this, you're able to ^solve* for one variable, plug that value in the equation and solve for the other variable.
Of course! I'd be happy to guide you through the process of solving these equations.
To solve this system of equations, we'll use the method of elimination. The goal is to eliminate one variable (either x or y) by multiplying both equations by suitable constants so that the coefficients of either x or y in both equations are additive inverses.
Step 1: Multiply both sides of the first equation by 8 and the second equation by 5 to make the coefficients of x or y additive inverses:
(8) * (4x - 5y) = (8) * 38 ---> 32x - 40y = 304
(5) * (7x - 8y) = (5) * (-22) ---> 35x - 40y = -110
Step 2: Now, subtract the second equation (35x - 40y = -110) from the first equation (32x - 40y = 304), which will eliminate the variable 'y':
(32x - 40y) - (35x - 40y) = 304 - (-110)
32x - 40y - 35x + 40y = 304 + 110
-3x = 414
Step 3: Divide both sides of the equation by -3 to solve for 'x':
(-3x) / (-3) = 414 / (-3)
x = -138
Step 4: Substitute the value of 'x' (-138) into either equation to solve for 'y'. Let's use the first equation:
4x - 5y = 38
4(-138) - 5y = 38
-552 - 5y = 38
-5y = 38 + 552
-5y = 590
Step 5: Divide both sides of the equation by -5 to find 'y':
(-5y) / (-5) = 590 / (-5)
y = -118
So, the solution to the system of equations is x = -138 and y = -118.