How many milliliters of 1.50 M \rm KOH solution are needed to provide 0.140 mol of \rm KOH
moles=volume*molarity
.140moles=V*1.50
solve for V in liters, then multipy it out by 1000 to get ml
5+56444
To find the number of milliliters of a 1.50 M \rm KOH solution needed to provide 0.140 mol of \rm KOH, we can use the formula:
\( \text{{molarity}} \times \text{{volume}} = \text{{moles}} \)
Let's rearrange the formula to solve for volume:
\( \text{{volume}} = \frac{{\text{{moles}}}}{{\text{{molarity}}}} \)
Now, substitute the given values into the formula:
\( \text{{volume}} = \frac{{0.140 \, \text{{mol}}}}{{1.50 \, \text{{M}}}} \)
Calculate the volume:
\( \text{{volume}} = \frac{{0.140}}{{1.50}} \, \text{{L}} \)
Since there are 1000 mL in 1 L:
\( \text{{volume}} = \frac{{0.140}}{{1.50}} \times 1000 \, \text{{mL}} \)
Now, compute the answer:
\( \text{{volume}} = 93.33 \, \text{{mL}} \)
Therefore, you would need 93.33 mL of a 1.50 M \rm KOH solution to provide 0.140 mol of \rm KOH.