How many ml of 50% dextrose should be added to 1 L of 0.9% NaCl to make a 5% dextrose solution?
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To answer this question, we need to understand how to calculate the amount of 50% dextrose needed to make a 5% dextrose solution.
First, let's identify the given information:
- We have 1 L of 0.9% NaCl.
- We want to make a 5% dextrose solution.
To calculate the amount of 50% dextrose solution needed, we need to determine the difference between the desired concentration (5%) and the existing concentration of dextrose in the 0.9% NaCl solution.
The existing concentration of dextrose in the 0.9% NaCl solution can be calculated using the formula:
Existing Concentration = (dextrose mass / total solution volume) * 100%
Since 0.9% NaCl solution contains only NaCl and no dextrose, the existing concentration of dextrose is 0%.
Hence, the difference between the desired concentration (5%) and the existing concentration (0%) is simply 5%.
To calculate the amount of 50% dextrose solution needed, we can use the formula:
Amount of 50% Dextrose = (difference in concentration * total solution volume) / desired concentration
In this case, the total solution volume is given as 1 L, and the desired concentration is 5%.
Plugging these values into the formula, we can calculate the amount of 50% dextrose needed:
Amount of 50% Dextrose = (5% * 1 L) / 50%
= (0.05 * 1 L) / 0.5
= 0.05 L / 0.5
= 0.1 L
Therefore, 0.1 L or 100 ml of 50% dextrose should be added to 1 L of 0.9% NaCl to make a 5% dextrose solution.