Perimeter is 60 ft. Find length and width if length is 8 ft longer than the width.

Would it be 60=(8+l)+w

I don't know where to put the 8
But there's two variables
how would I find both l and w

P = 2L + 2W

L = W + 8

60 = 2(W+8) + 2W
60 = 2W + 16 + 2W
60 = 4W + 16
60 - 16 = 4W
44 = 4W
11 = W

? = L

thank you

You're welcome.

To find both the length and width, we can start by defining the variables. Let's let "l" represent the length and "w" represent the width.

Given that the length is 8 feet longer than the width, we can express the length as l = w + 8.

The perimeter of a rectangle is calculated by adding up all of its side lengths. In this case, we know that the perimeter is 60 feet.

The formula for the perimeter of a rectangle is given by P = 2(l + w), where P represents the perimeter.

Substituting the given values, we have 60 = 2((w + 8) + w).

To simplify further, we distribute the 2 and combine like terms:

60 = 2w + 16 + 2w.
60 = 4w + 16.

Next, we can isolate the variable w:

60 - 16 = 4w,
44 = 4w,
w = 11.

We have now found the value of w, which represents the width.

To find the length, we substitute the width back into the equation l = w + 8:

l = 11 + 8,
l = 19.

Therefore, the width is 11 ft and the length is 19 ft.