physics
posted by Katie .
A rock is dropped from a sea cliff, and the sound of it striking the ocean is heard 3.3 later. If the speed of sound is 340 , how high is the cliff?

You need to show the units of your numbers. I will assume they are meters and seconds.
Solve this equation for height, H:
3.23 s = time for sound to arrive + time to fall
3.3 = H/340 + sqrt(2H/9.8) 
1.3 (using the given equation...)

Given:
t=5sec.
Vo=0m/s
g=9.81m/s^2
V=320m/s^2
Solution:
H=Vot+0.5gt^2
H=(0.5)(9.81)(5^2)
H=122.625m
H=vt
H=320(5)
H=1600m
H=122.625+1600
[H=1722.625m] :) 
Given:
t=3.3sec.
Vo=0m/s
g=9.81m/s^2
V=340m/s^2
Solution:
H=Vot+0.5gt^2
H=(0.5)(9.81)(3.3^2)
H=53.42m
H=vt
H=340(5)
H=1700m
H=53.42+1700
[H=1753.42m] :)
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