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A rock is dropped from a sea cliff, and the sound of it striking the ocean is heard 3.3 later. If the speed of sound is 340 , how high is the cliff?

  • physics -

    You need to show the units of your numbers. I will assume they are meters and seconds.

    Solve this equation for height, H:

    3.23 s = time for sound to arrive + time to fall

    3.3 = H/340 + sqrt(2H/9.8)

  • physics -

    1.3 (using the given equation...)

  • physics -

    Given:
    t=5sec.
    Vo=0m/s
    g=9.81m/s^2
    V=320m/s^2
    Solution:
    H=Vot+0.5gt^2
    H=(0.5)(9.81)(5^2)
    H=122.625m

    H=vt
    H=320(5)
    H=1600m

    H=122.625+1600
    [H=1722.625m] :)

  • physics -

    Given:
    t=3.3sec.
    Vo=0m/s
    g=9.81m/s^2
    V=340m/s^2
    Solution:
    H=Vot+0.5gt^2
    H=(0.5)(9.81)(3.3^2)
    H=53.42m

    H=vt
    H=340(5)
    H=1700m

    H=53.42+1700
    [H=1753.42m] :)

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