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A car makes a 60-km trip with an average velocity of 38.5-km/h in a direction due north. The trip consists of three parts. The car moves with a constant velocity of 25 km/h due north for the first 15 km and 62 km/h due north for the next 32 km. With what constant velocity does the car travel for the last 13-km segment of the trip?

  • physics -

    average velocity= total distance/total time

    Time for first leg: 15/25 hr
    Time for second leg: 32/62
    Time for third leg...

    total time=60/38.5=you do it.
    time for third leg= distance/timethird=
    = 13/(totaltime-15/25 - 32/62)

    velocity on third leg= 13/time for third

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