two ropes are attached to a 200. kg sled. A 490. newton dog attached to on eo the ropes applies a force of 300. N b north of the rope. A 35.0 kg dog attached to the second rope applies a force of 125 N b 36.9 degrees south of west to the rope. Calculate the net force applies to the sled. (vector diagrams reequired)
Fy = North pull = 300 - 125 sin 36.9
Fx = East pull = -125 cos 36.9
|F| = sqrt(Fx^2+Fy^2)
tan angle north of east = Fy/Fx
remember in quadrant 2
To calculate the net force applied to the sled, we need to add up the individual forces applied by the dogs. To do this, we can break down each force into its components using vector diagrams.
Let's start by calculating the components of the force applied by the 490 N dog. Since the force is applied directly north, there is no horizontal (east-west) component, and the entire force is in the north direction.
Next, let's calculate the components of the force applied by the 35.0 kg dog. The force of 125 N is applied 36.9 degrees south of west. To determine the horizontal (east-west) component, we'll use the cosine function:
Horizontal component = 125 N * cos(36.9°)
To determine the vertical (north-south) component, we'll use the sine function:
Vertical component = 125 N * sin(36.9°)
Now that we have the components for both dogs' forces, we can add them up to find the net force.
Horizontal net force = 0 N (since there is no horizontal component for the 490 N dog)
Vertical net force = Sum of vertical components = (125 N * sin(36.9°))
Now, to find the net force, we need to combine the horizontal and vertical components:
Net force = √(Horizontal net force)^2 + (Vertical net force)^2
Substitute the values and calculate:
Net force = √(0 N)^2 + ((125 N * sin(36.9°))^2)
Finally, calculate the net force to get the answer.