If Sandy usually earns $88 plus 11% sales each week. What if she earns $154 one week. What is the % sales she earned that week when she earned $154?

Would the answer be 600?

Yes. That's correct.

Would you know how to get the answer 600 because I solved it differently and did not get 600

Here's what I did.

154 - 88 = 66

0.11x = 66
x = 600

I thought I had cross multiply.

88/154 = .11/x

Your fractions for the proportion are not equivalent.

Do you understand what I did?

yes

No, the answer is not 600. To find the percentage of sales Sandy earned in a particular week when she earned $154, you need to calculate it based on the given information.

First, let's find out how much Sandy earned from sales that week. We know that her base amount is $88, and she earns an additional 11% of her sales. Let's represent the sales amount as 'x'.

$sales = base amount + 11% of sales
$154 = $88 + (11% of x)

Next, we'll calculate the value of 'x'.

$154 - $88 = (11/100) * x
$66 = (11/100) * x

To solve for 'x', divide both sides of the equation by (11/100).

x = ($66 * 100) / 11
x = $600 / 11
x ≈ $54.55

So, Sandy earned approximately $54.55 from sales that week.

To find the percentage sales she earned, divide the sales amount ($54.55) by her base amount ($88), then multiply by 100 to convert to a percentage.

Percentage sales earned = (sales amount / base amount) * 100
Percentage sales earned = ($54.55 / $88) * 100 ≈ 61.92%

Thus, Sandy earned approximately 61.92% sales that week when she earned $154.