The concentration of a benzene solution prepared by mixing 12.0 g C6H6 with 38.0 g CCl4 is__________ molal.

Thanks for the help, is this right?

12.0/78.12=0.1536

0.1536/0.038=4.04

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moles C6H6 = grams/molar mass C6H6.

m = moles C6H6/kg solvent.

Yup

Well, it seems like you've got quite the chemical cocktail going on there! Mixing benzene with carbon tetrachloride, huh? That's quite the experiment. Now, to answer your question about the concentration of this concoction, we need to calculate the molality.

Molality is defined as the moles of solute per kilogram of solvent. So, let's get those numbers crunching, shall we?

First, we need to calculate the moles of each substance.

For benzene (C6H6):
Molar mass of C6H6 = 6(12.01 g/mol) + 6(1.01 g/mol) = 78.11 g/mol

Moles of C6H6 = mass of C6H6 / molar mass of C6H6
Moles of C6H6 = 12.0 g / 78.11 g/mol

For carbon tetrachloride (CCl4):
Molar mass of CCl4 = 12.01 g/mol + 4(35.45 g/mol) = 153.82 g/mol

Moles of CCl4 = mass of CCl4 / molar mass of CCl4
Moles of CCl4 = 38.0 g / 153.82 g/mol

So, now we have the moles of solute and solvent. We can now calculate the molality:

Molality = moles of solute / mass of solvent (in kg)

Since we are using 38.0 g of carbon tetrachloride, we need to convert that to kilograms:

Mass of CCl4 = 38.0 g = 0.038 kg

Now, we can calculate the molality:

Molality = moles of C6H6 / mass of CCl4 (in kg)
Molality = (12.0 g / 78.11 g/mol) / 0.038 kg

And there you have it! Once you do the math, you'll get your answer in molal. Just make sure to keep an eye out for any jokes that may have accidentally slipped into those chemical calculations.

To determine the molality (molal concentration) of a solution, we need to calculate the molality by using the formula:

Molality (m) = moles of solute / mass of solvent (in kg)

Here's how you can calculate the molality of the benzene solution:

Step 1: Calculate the moles of benzene (C6H6):
Given that the mass of C6H6 (benzene) is 12.0 g, we can use its molar mass to convert this to moles.
The molar mass of C6H6 is:
(6 * Atomic mass of carbon) + (6 * Atomic mass of hydrogen) = (6 * 12.01 g/mol) + (6 * 1.01 g/mol) = 72.06 g/mol

Using the formula: moles = mass / molar mass, we can calculate the moles of benzene:
moles of benzene = 12.0 g / 72.06 g/mol

Step 2: Calculate the mass of the solvent (CCl4):
Given that the mass of CCl4 is 38.0 g.

Step 3: Convert the mass of the solvent in grams to kilograms:
mass of solvent (CCl4) = 38.0 g / 1000 = 0.038 kg

Step 4: Calculate the molality (m) using the formula:
molality = moles of solute (benzene) / mass of solvent (CCl4)

Substituting the values we found in steps 1-3, we get:
molality = (12.0 g / 72.06 g/mol) / 0.038 kg

Now you can calculate the molality to find the concentration of the benzene solution.