Post a New Question

math

posted by .

f(x) = x^2 + 10x + 24
=(x^2 + 10x)+ 24
=(x^2 + 10x + 25 - 25) + 24
f(x) =(x+5)^2 - 1

Vertex: (-5, -1)

How do you sketch this? I know that in the graph one of the coord is (-5, -1) but how do I find the others in order to make a parabola? :|

  • math -

    Factorize to get the zeroes:
    f(x)=x²+10x+24=(x+6)(x+4)
    Therefore the zeroes at at x=-6, x=-4.

    The y-intercept is y=24 (= constant term)
    The coefficient of x² is positive, so the curve is concave upwards.

    The vertex is the minimum of the parabola, and x=-5 passing through the vertex is the axis of symmetry.

    That should give enough information to sketch the graph?

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

More Related Questions

Post a New Question