molal (again)

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i tried to solve it on my own but im confused about the last part, this i what i have so far..

moles of glycerin= 50.0/92.10=0.54
molality=0.54/0.200=2.7
is that right?

im a little confused about the numbers im supposed to use for step 3...

this was the question:

the freezing point of ethanol (C2H5OH) is -114.6C. the molal freezing point depression constant for ethanol is 2.00C/m. what is the freezing point (C) of a solution prepared by dissolving 50.0 g of glycerin (C3H8O3, A nonelectrolyte) in 200 g of ethanol.

  • molal (again) -

    yes,

    molal= molessolute/kgsolvent
    You have it correct.

  • molal (again) -

    im not sure about the last step tho... i know the final answer is -120.0 but im not sure how to get to that...

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