factor each polynomial
36p^2-49q^2
Note that it is the difference of two squares: the squares of 6p and 7q.
That should give you a clue.
Also recall that a^2 - b^2 = (a+b)(a-b)
Drwls- Unfortunately your hints do not help as I have no clue how to even start the problem. Please do the problem and then maybe I will understand.
(6p)^2 - (7q)^2
factor it as drwls showed.
To factor the polynomial 36p^2 - 49q^2, we can use the difference of squares formula.
The difference of squares formula states that for any two terms A and B,
A^2 - B^2 = (A + B)(A - B)
In this case, A = 6p and B = 7q.
So, applying the difference of squares formula, we have:
36p^2 - 49q^2 = (6p + 7q)(6p - 7q)
Therefore, the factored form of the polynomial 36p^2 - 49q^2 is (6p + 7q)(6p - 7q).