# College Physics

posted by
**Anonymous**
.

A particle is moving in the xy plane with constant acceleration. At t=o, the particle is given by x=4m, y=3m, and has a velocity v=2m/s x-hat - 9m/s y-hat. The acceleration of the particle is given by a=4m/s^2 x-hat + 3m/s^2 y-hat. Find the velocity vector at t=2 seconds.

My only problem is i don't know which equation to use. I thought it would be V=Vo+a*t but I need to use the x component (displacement) & if i use V^2=Vo^2+2a*deltaX then I need a component for time which this equation doesnt have.