# algebra

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the perimeter of a rectangle is 222 inches. the length exceeds the width by 47 inches. what is the length and width

• algebra -

width -- x
length -- x+47

solve
2(x + x+47) = 222

• algebra -

P=2l +2w
222 = 2(w+47) + 2w
222= 2w +94 +2w
222=4w+94
222-94=4w+94-94
128=4w
32=w so length = w+47
length = 32+47=79

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