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y=4x^2-16x+12

4(x^2-4x+3)
You can factor this further by seeing which 2 numbers subtract to 4 (your middle term) and add to 3 (your last term). Post if you want it checked/need help.

4[x^2-3x-x+3]
=4[x[x-3)-1(x-3)]
=4[x-1][x-3]

4[x-1][x-3]

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