SrH2 +2H2O = Sr(OH)2 + 2H2

You wish to calculate the mass of hydrogen gas that can be prepared from 7.74g of SrH2 and 6.45g of H2O How many moles of H2 can be produced from the given mass of SrH2? How many moles of H2 can be produced from the given mass of H2O?

I think this was posted later (and answered).

I dunno know

To calculate the moles of H2 that can be produced from the given mass of SrH2 and H2O, we need to use the molar masses of these compounds and apply stoichiometry.

1. Calculate the moles of SrH2:
The molar mass of SrH2 is determined by summing the atomic masses of its constituent elements. In this case, strontium (Sr) has a molar mass of 87.62 g/mol, and hydrogen (H) has a molar mass of 1.01 g/mol.

Molar mass of SrH2 = atomic mass of Sr + (2 * atomic mass of H)
= 87.62 g/mol + (2 * 1.01 g/mol)
= 89.64 g/mol

Now, use the formula:
moles of SrH2 = mass of SrH2 / molar mass of SrH2

moles of SrH2 = 7.74 g / 89.64 g/mol
= 0.0863 mol

Therefore, from 7.74 g of SrH2, we can produce 0.0863 moles of H2.

2. Calculate the moles of H2O:
The molar mass of H2O is calculated similarly. Oxygen (O) has a molar mass of 16.00 g/mol, and hydrogen (H) has a molar mass of 1.01 g/mol.

Molar mass of H2O = (2 * atomic mass of H) + atomic mass of O
= (2 * 1.01 g/mol) + 16.00 g/mol
= 18.02 g/mol

Using the formula:
moles of H2O = mass of H2O / molar mass of H2O

moles of H2O = 6.45 g / 18.02 g/mol
= 0.358 mol

Therefore, from 6.45 g of H2O, we can produce 0.358 moles of H2.