How many grams of Li3N can theoretically be produced from 1.77 moles of Li? 6Li+N2 = 2Li3N

Look at the coefficients in the balanced equation. They tell you how the reactions takes place.

To find the theoretical yield of Li3N, we need to use the balanced chemical equation and the stoichiometry of the reaction.

First, let's determine the molar ratio between Li and Li3N using the balanced chemical equation: 6 Li + N2 → 2 Li3N

From the equation, we can see that 6 moles of Li react to form 2 moles of Li3N.

Next, we can set up a proportion to determine the moles of Li3N produced from 1.77 moles of Li:

(2 moles of Li3N / 6 moles of Li) = (x moles of Li3N / 1.77 moles of Li)

Simplifying the equation, we get:

x = (2/6) * 1.77 = 0.59 moles of Li3N

Now, we can determine the molar mass of Li3N. The atomic masses of Li and N are approximately 6.94 g/mol and 14.01 g/mol, respectively.

The molar mass of Li3N can be calculated as follows:

(3 moles of Li * 6.94 g/mol) + (1 mole of N * 14.01 g/mol) = 29.73 g/mol

Finally, we can calculate the mass of Li3N using the moles of Li3N and its molar mass:

Mass = Moles × Molar mass
Mass = 0.59 moles × 29.73 g/mol = 17.51 grams of Li3N

Therefore, theoretically, 17.51 grams of Li3N can be produced from 1.77 moles of Li.