finite math
posted by carly .
Assume that the student
has a cup with 15 writing implements: 8 pencils, 5 ball
point pens, and 2 felttip pens.In how many ways can the selection be made if no more than one ball
point pen is selected?

"In how many ways can the selection be made if no more than one ball point pen is selected?"
your question is not clear.
Are the pencils all the same ? etc
Is one ballpoint, 6 pencils and 2 felttips a "selection" ?
Is just one pencil a "selection" ?
You have to define what you mean by a selection. 
I thought it over and I would do it this way:
the pencils can be taken in 9 ways, that is,
take none, 1,2,3,.. or 8 of them
the ballpoint pens can be taken in 2 ways, none or 1
the felttips in 3 ways, none, one or both.
number of selections = 9(2)(3) or 54
But that would include the case of taking none at all, which would not be a selection,
so number of selections is 541 or
53 ways. 
I don't know the answer but i know the answer is not 53. Not all info was givin to complete the problem. It should have read that they student will select 5 writing implements. How many ways if only one ball poin at selected.
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