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A hockey puck sliding on a frozen lake comes to rest after traveling 160 m.
If its initial velocity is 2.3 m/s, what is its acceleration (assumed constant)?
Answer in units of m/s2.

  • Physics -

    The distance = (1/2)*(acceleration)*(time)^2 + (initial velocity)*(time)

    acceleration= (final velocity-initial velocity)/time

    The distance = (1/2)*[(final velocity-initial velocity)/time]*(time)^2 + (initial velocity)*(time)

    Find time & plug back into acceleration formula!

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