Physics
posted by STOW .
A hockey puck sliding on a frozen lake comes to rest after traveling 160 m.
If its initial velocity is 2.3 m/s, what is its acceleration (assumed constant)?
Answer in units of m/s2.

Physics 
TutorCat
The distance = (1/2)*(acceleration)*(time)^2 + (initial velocity)*(time)
substitute:
acceleration= (final velocityinitial velocity)/time
The distance = (1/2)*[(final velocityinitial velocity)/time]*(time)^2 + (initial velocity)*(time)
Find time & plug back into acceleration formula!
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