I need serious help with 3 different chemistry problems:
1. If coal is assumed to be all carbon, carbon has a molecular weight of 12 lb-mass/lb-mol, and oxgyen (diatomic) has a molecular weight of 32 lb-mass/lb-mol, how much carbon dioxide (lb-mass/day) is produced in 171.4 lb./day?
2. A quantity k depends on the temperature T in the following manner:
k(mol/cm^3xs)= 1.2 x 10^5 exp(-20,000/1.987T)
The units of the quantity 20,000 are cal/mol, and T is in K. What are the units of 1.2 x 10^5 and 1.987?
1. Wouldn't the molar mass CO2 be 44.
171.4 x (1/12) = moles CO2
lb CO2 = (171.4/12) x (44 lb CO2/mol) = ??
Sure, I can help you with these chemistry problems. Let's tackle them one by one:
1. To find how much carbon dioxide is produced, we need to calculate the amount of carbon in the given quantity of coal and then convert it to carbon dioxide.
The molecular weight of carbon is 12 lb-mass/lb-mol. So, the amount of carbon in 171.4 lb./day can be calculated by dividing the given quantity by the molecular weight:
Amount of carbon = 171.4 lb./day / 12 lb-mass/lb-mol = 14.283 mol/day
Since coal is assumed to be all carbon, this also represents the number of moles of carbon dioxide produced. Now, we need to convert mol/day to lb-mass/day. The molecular weight of carbon dioxide is 44 lb-mass/lb-mol.
Amount of carbon dioxide = 14.283 mol/day * 44 lb-mass/lb-mol = 628.116 lb-mass/day
Therefore, approximately 628.116 lb-mass/day of carbon dioxide is produced.
2. In the given equation, the quantity 1.2 x 10^5 is a constant and 1.987 is a coefficient.
The units of 1.2 x 10^5 depend on the quantity k, which is in mol/cm^3. Therefore, the units of 1.2 x 10^5 are mol/cm^3.
The quantity 1.987 is the ideal gas constant, which has a value of 1.987 cal/(mol K). The units of the ideal gas constant are cal/(mol K), where cal stands for calories and K stands for Kelvin.
So, the units of 1.2 x 10^5 are mol/cm^3 and the units of 1.987 are cal/(mol K).
I hope this explanation helps you understand how to solve these chemistry problems! Let me know if you need any further assistance.