T is in the interior of angle"PQR". if angle"PQR"=10X-7, angle"RQT"=5X and angle"PQT"=4x+6 "X" will eaqual to?
My question is a bit different then this
It’s 123
why its 13 i didn't get it could u give me several steps
Par
To find the value of X, we need to use the given information about the angles. Let's break down the problem step by step.
1. Angle PQR is the sum of angles PQT and RQT.
PQR = PQT + RQT
10X - 7 = 4X + 6 + 5X
Combine like terms:
10X - 7 = 9X + 6
2. Now, let's solve the equation for X by isolating the variable on one side.
Subtract 9X from both sides:
10X - 9X - 7 = 9X - 9X + 6
X - 7 = 6
3. Add 7 to both sides:
X - 7 + 7 = 6 + 7
X = 13
Therefore, X equals 13.
PQT + RQT = PQR,
(4X + 6) + 5X = 10X - 7,
4X + 5X - 10X = -7 - 6,
-X = -13,
X = 13.