In the Lewis structure for SF4, there are:
a. 12 electrons surrounding the S.
b. 10 electrons surrounding the S
c. a total of 42 valence electrons.
d. Both a and c are correct.
e. None of the above are correct
sulfur has 16 electrons total (according to the atomic number; 2 (most inner), 8 (next inner), 6 (further from core; aka valence electrons)
fluorine has 9 electrons total; 2(inner), 7 (outer; aka valence electrons)
I count 10 electrons around S.
To determine the Lewis structure for SF4, we need to consider the valence electrons of each atom involved.
Sulfur (S) is in Group 16 of the periodic table, so it has 6 valence electrons. Fluorine (F) is in Group 17, so it has 7 valence electrons.
To find the number of valence electrons in SF4, we add the valence electrons of sulfur (6) to the valence electrons of four fluorine atoms (4 x 7 = 28).
Therefore, the correct answer is:
c. a total of 42 valence electrons.