1. At 11:00 a.m. a one-meter-high mailbox casts a 0.7-meter shadow. If a pole beside the mailbox casts a 28-meter shadow, how tall is that pole?
400 m
40 m
0.4 m
4 m
A Squared + B squared = C squared
I don't understand.????
The Pythagorean theorem is not needed here.
They are proportional.
1/.7 = x/28
Multiply both sides by 28.
28/.7 = x = ?
40 m
To find the height of the pole, we can use the property of similar triangles. Here's how to solve the problem step by step:
1. Start by setting up a proportion between the height of the mailbox and its shadow length:
mailbox height / mailbox shadow length = pole height / pole shadow length
2. Substitute the given values into the proportion:
1 meter / 0.7 meter = x / 28 meters
Simplify the proportion:
1.4286 = x / 28
3. Cross-multiply to solve for x (the height of the pole):
1.4286 * 28 = x
x ≈ 39.9992 meters
Since x represents the height of the pole, we can approximate it to 40 meters. Therefore, the answer is 40 m.