a glass container was filled with oil with a density of 0.80 g/cm^3 up to 9 cm. in height.

1) what is the pressure at the base of the container?

2) what is the depth if 3 cm. from the surface of the oil?

3) what is the depth if 4 cm. above the base?

the pressure is ether 30 or a 10

To answer these questions, we need to use the concept of fluid pressure. The pressure at a certain depth in a fluid is given by the equation:

Pressure = Density * Gravitational Acceleration * Depth

Where:
- Pressure is the pressure at the given depth (in Pascals, Pa)
- Density is the density of the fluid (in kilograms per cubic meter, kg/m^3)
- Gravitational Acceleration is the acceleration due to gravity (approximately 9.8 m/s^2)
- Depth is the vertical distance from the surface to the point of interest (in meters, m)

Now, let's apply this equation to the given information:

1) For the pressure at the base of the container, the depth is equal to the height of the container, which is 9 cm or 0.09 m. The density of the oil is 0.80 g/cm^3. To convert it to kg/m^3, we multiply by 1000 since there are 1000 grams in a kilogram. Thus, the density is 800 kg/m^3. Plugging these values into the equation:

Pressure = 800 kg/m^3 * 9.8 m/s^2 * 0.09 m = 705.6 Pa

Therefore, the pressure at the base of the container is 705.6 Pa.

2) For the depth of 3 cm from the surface of the oil, the depth is 3 cm or 0.03 m. Plugging this value into the equation:

Pressure = 800 kg/m^3 * 9.8 m/s^2 * 0.03 m = 235.2 Pa

Therefore, the pressure at a depth of 3 cm from the surface of the oil is 235.2 Pa.

3) For the depth of 4 cm above the base, we need to subtract the depth from the total height of the container. The total height is 9 cm or 0.09 m. So, the depth would be 0.09 m - 0.04 m = 0.05 m. Plugging this value into the equation:

Pressure = 800 kg/m^3 * 9.8 m/s^2 * 0.05 m = 392 Pa

Therefore, the pressure at a depth of 4 cm above the base is 392 Pa.