posted by Ed .
Find the value of the following.
The log exponent is confusing me. Could someone please help me? Thanks.
-10log3= log3^-10= log (1/3^10)
so 10^(log(1/3^10)= 1/3^10
Here is an unconfusing explanation.
so 10^2=l0^(log100) by definition.
Have you come across the property of logs that says ..
a^loga k = k
your question fits that pattern after a quick adjustment
= 10^(log 3^(-10))
= 1/3^10 , so far no calculator
= appr. .000016935
log3 = .47771213
-10log3 = -4.771213
10^-4.771213 = .00016935